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Check Whether Given Number is Armstrong or Not
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Article:
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Viewed:
1738
Posted On:
24/07/2013 04:13:48
Hi all,With the help of this article i am going to tell you that how we can check for the number to be armstrong number........
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Below is my code:
import
java.util.Scanner;
class
armstrongI
{
public
static void main(String s[])
{
int
a,b,c=0,d;
System.out.println("enter no. ");
Scanner
scan=new Scanner(System.in);
a=scan.nextInt();
System.out.println("you
entered ="+a);
b=a;
while(a!=0)
{
d=a%10;
c=c+d*d*d;
a=a/10;
}
if(c==b)
{
System.out.println("no
is armtrong");
}
else
{
System.out.println("no.
is not armstrong");
}
}
}
Step 1: After
writing this in notepad save the file with the name followed by (.java) for eg. I saved it with armstrong.java
Step 2 : Open command prompt
Step 3 : Write javac armstrong.java - Press
Enter for compilation
Step 4
: Write java
armstrong for execution
Output:
Image 1.
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