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Check Whether Given Number is Armstrong or Not

Article:
Viewed:  918 
Posted On:  24/07/2013 04:13:48 
Hi all,With the help of this article i am going to tell you that how we can check for the number to be armstrong number........ 

 

Below is my code:


import java.util.Scanner;
class armstrongI
{
public static void main(String s[])
{
int a,b,c=0,d;
System.out.println("enter  no. ");
Scanner scan=new Scanner(System.in);
a=scan.nextInt();
System.out.println("you entered ="+a);
b=a;
while(a!=0)
{
d=a%10;
c=c+d*d*d;
a=a/10;
}
if(c==b)
{
System.out.println("no is armtrong");
}
else
{
System.out.println("no. is not armstrong");
}
 }
}

  Step 1:
  After writing this in notepad save the file with the name followed by (.java) for eg. I saved it with armstrong.java

 Step 2 : 
Open command prompt 

 Step 3 : 
Write javac armstrong.java - Press Enter for compilation

 Step 4 : 
Write java armstrong for execution

Output:

Armstrong.png

Image 1.

  Comment:
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